Mensuration - Quant/Math - CAT 2008
Question 4 the day:
September 01, 2003
The question for the day is from the topic of Mensuration.
- If the sides of a triangle measure 72, 75 and 21, what is the measure of
its in radius?
(1) |
37.5 |
|
|
(2) |
24 |
(3) |
9 |
|
|
(4) |
15 |
Correct Answer - (3)
Solution:
The sides of the triangle happen to be a Pythagorean triplet. Hence, the
triangle is a right angled triangle.
For a right angled triangle,
The measure of in radius = (product of perpendicular sides) / (perimeter of
triangle)
= (72 * 21) / (72 + 21 +75) = 1512 / 168 = 9
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