Geometry - Quant/Math - CAT 2008
Question 4 the day: March
03, 2003
The question for the day is from the topic of Geometry
- Find the area of the triangle whose vertices are (-6, -2), (-4, -6),
(-2, 5).
(1) |
36 |
|
|
|
(2) |
18 |
(3) |
15 |
|
|
|
(4) |
30 |
Correct Answer - (3)
Solution:
The area of the triangle formed by the vertices A (X1, Y1);
B (X2, Y2) and C (X3, Y3) is given
by
X1 - X2
1/2 [
]
X2 - X3
The area of triangle whose verticles are (-6, -2), (-4, -6), (-2, 5) is given
-2 +6
by [
]
-6 -5
-2 +4
1/2 [
]
-2 -11
1/2[ 22- (-8) = 15 sq unit
|