The question for the day is from the topic of Geometry.
If ABC is a right angle triangle with angle A = 900 and 2s = a + b + c,
where a > b > c where notations have their usual meanings, then which one of
the following is correct?
(1)
(s � b) (s � c) > s (s � a)
(2)
(s � a) (s � c) > s (s � b)
(3)
(s � a) (s � b) < s (s � c)
(4)
4s (s � a) (s � b) (s � c) = bc
Correct Answer - (3) Solution:
Let a = 5, b = 4 & c = 3
Since it is a right angle triangle and 3, 4 and 5 are pythogorean triplet.
s = (a + b + c)/2 = 12/2 = 6
Substitute these values and check which condition satisfies this.
Let us take choice(3)
L.H.S
(s � a) (s � b) = (6 - 5)(6 - 4) = 2.
R.H.S
s(s � c) = 6(6 � 3) = 18.
L.H.S < R.H.S
It satisfies the given condition hence Choice(3) is the right answer.