Races - Quant/Math - CAT 2008
Question 4 the day:June
2, 2003
The question for the day is from the topic of Races.
- P can give Q a start of 20 seconds in a kilometer race. P can give R a
start of 200 meters in the same kilometer race. And Q can give R a start of
20 seconds in the same kilometer race. How long does P take to run the
kilometer?
(1) |
200 seconds |
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(2) |
240 seconds |
(3) |
160 seconds |
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(4) |
140 seconds |
Correct Answer - (3)
Solution:
P can give Q a start of 20 seconds in a kilometer race. So, if Q takes 'x'
seconds to run a kilometer, then P will take x � 20 seconds to run the
kilometer.
Q can give R a start of 20 seconds in a kilometer race. So, if R takes 'y'
seconds to run a kilometer, then Q will take y � 20 seconds to run the
kilometer.
We know Q takes x seconds to run a kilometer
Therefore, x = y � 20
Therefore, P will take x � 20 = y � 20 � 20 = y � 40 seconds to run a kilometer.
i.e. P can give R a start of 40 seconds in a kilometer race, as R takes y
seconds to run a kilometer and P takes only y � 40 seconds to run the kilometer.
We also know that P can give R a start 200 meters in a km race.
This essentially means that R runs 200 meters in 40 seconds.
Therefore, R will take 200 seconds to run a km.
If R takes 200 seconds to run a km, then P will take 200 � 40 = 160 seconds to
run a km.
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