Work and Time - Quant/Math - CAT 2008
Question 4 the day: June
6, 2002
The question for the day is from the topic work and time.
- Four men and three women can do a job in 6 days. When five men and six
women work on the same job, the work gets completed in 4 days. How long will
a woman take to do the job, if she works alone on it?
(1) |
18 days |
|
(2) |
36 days |
|
(3) |
54 days |
|
(4) |
None of these |
Correct Answer - (3)
Solution:
Let the amount of work done by a man in a day be �m� and the amount of work done
by a woman in a day be �w�.
Therefore, 4 men and 3 women will do 4m + 3w amount of work in a day. If 4 men
and 3 women complete the entire work in 6 days, they will complete 1/6th of the
work in a day.
Hence eqn (1) will be 4m + 3w = 1/6
and from statement (2), eqn (2) will be 5m + 6w = 1/4
Solving eqn (1) and eqn (2), we get 3m =1/12
or m = 1/36. i.e. a man does 1/36th of the work in a day. Hence he will take 36
days to do the work.
Substituting the value of m in eqn (1), we get 4 * 1/36 + 3w =
1/6
=> 3w =1/6-1/9 = 3-2 / 18 = 1/18
or w = 1/54. i.e. a woman does 1/54th of the work in a day. Hence she will take
54 days to do the entire work.