- A, B and C can do a work in 5 days, 10 days and 15 days respectively.
They started together to do the work but after 2 days A and B left. C did
the remaining work (in days)
(1) 1 (2) 3 (3) 5 (4) 4
Solution:
If A, B and C work together for a day then they will finish (1/5 + 1/10 + 1/15)th work = 11/30th work.
Therefore working together for two days they will finish 2 * 11/30 = 11/15th work.
C alone does remain (11/15 � 1) 4/15th work.
But C finishes 1/15th work in one day. Therefore C will finish 4/15th work in 4 days.