The question for the day is from the topic of Probability.
A number is selected at random from first thirty natural numbers. What
is the chance that it is a multiple of either 3 or 13?
(1)
17/30
(2)
2/5
(3)
11/30
(4)
4/15
Correct Answer - (2) Solution:
The probability that the number is a multiple of 3 is 10/30. (Since 3*10 = 30).
Similarly the probability that the number is a multiple of 13 is 2/30. {Since
13*2 = 26).
Neither 3 nor 13 has common multiple from 1 to 30. Hence these events are
mutually exclusive events. Therefore chance that the selected number is a
multiple of 3 or 13 is (10+2)/30 = 2/5